x^2=0.15386-180x

Solution for x^2=0.15386-180x equation:

x^2=0.15386-180x

We move all terms to the left:

x^2-(0.15386-180x)=0

We add all the numbers together, and all the variables

x^2-(-180x+0.15386)=0

We get rid of parentheses

x^2+180x-0.15386=0

a = 1; b = 180; c = -0.15386;
Δ = b2-4ac
Δ = 1802-4·1·(-0.15386)
Δ = 32400.61544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-\sqrt{32400.61544}}{2*1}=\frac{-180-\sqrt{32400.61544}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+\sqrt{32400.61544}}{2*1}=\frac{-180+\sqrt{32400.61544}}{2}
$